Question

a car starts from rest and moves with constant acceleration the ratio of distance covered by ​

Answer 1

Answer:

Distance covered in n seconds is simply calculated by 2nd equation of motion…..

S(n)= un + 1/2(a) (n^2)

Where u=0 becoz object is at rest initially so it become s(n)= 1/2(a)(n^2)

#Distance covered in nth second is define as distance covered from (n) to (n+1) second which comes as s(nth)= (a/2)×(2n+1).

Hence ratio will comes as (2n+1)/(n^2).