A car starts from rest and moves with constant acceleration along a straight line. If S3 and
S4 are its displacement in 3rd and 4th second respectively, then:
(A) S3 > S4
(C) S3 = S4
(B) S3
(D) information insufficient
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Answer:
I think b is S3<S4
Explanation:
because the car is moving with a constant acceleration and the car starts from rest so it doesn't matter that acceleration is negative or positive so 3rd second increase in velocity(v3) is less than 4th second velocity(v4). Due to this the displacement(v×t) will be greater in 4th second,due to greater velocity.
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