Question

A car starts from rest and moves with uniform acceleration if 2m/s2
how much time it takes to cover 49m distance?

Answer 1

HEYA!
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Using second equation of motion,

$s = ut + \frac{1}{2} at {}^{2}$
Putting values


$49 = 0 \times t + \frac{1}{2} \times 2 \times t {}^{2}$
$49 = t {}^{2} \\ \\ = > t = 7$
Hence time is 7 seconds .

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Answer 2

Answer:

ans is 7;secs

Explanation:

a = 2 m/s

t=

s= 49 m

formula to use

s= ut + 1/2 at ^2

49= 0× t + 1/2 2× t^2

49=t^2

t = 7

hence time (t) is 7 secs