Question

a car starts from rest and obtained a velocity 30m/s in three second. calculate acceleration amd displacement

Answer 1

acceleration = (v-u)/t
a= (30-0)/3
a= 30/3=10m/s^2

displacement = ut+1/2 at^2
0×3+1/2×10×9
45 m

Answer 2

As the car starts from rest,

u=0

According to the question

v=30

t=3

So using first law of motion

v=u+at

30 =0+3a

3a=30

a=10 meter per second square

Now in this case displacement = distance, so distance is

S =ut+1/2at^2(second law of motion)

S=0+1/2*10*3^2

s=5*9

s=45m