Question

A car starts from rest aquores a velocity 72km/h in 10 sec. Find rhe acceleration amd force applies onthe body

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=2\:m/s^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Initial \: velocity(u) = 0 \: km/h \\ \\ \tt: \implies Final \: velocity( v ) = 72 \: km/h \\\\ \tt: \implies Time( t) = 10 \: sec \\ \\ \red{\underline \bold{To \: Find:}}\\ \tt: \implies Acceleration(a) = ?$

• According to given question :

$\tt \circ \: Initial \: velocity =0 \: m/s \\ \\ \tt \circ \: Final \: velocity = 72\times \frac{5}{18}=20 \: m/s \\ \\ \tt \circ \: Time = 10\: sec \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 20= 0 + a \times 10 \\ \\ \tt: \implies 20 =10\times a \\ \\ \tt: \implies a = \frac{20}{10} \\ \\ \green{\tt: \implies a =2 \: m/{s}^{2} }$

$\blue{ \bold{some \: related \: formula}} \\ \orange{\tt \circ \: {v}^{2} = {u}^{2} + 2as} \\ \\ \orange{\tt \circ \: s = ut + \frac{1}{2} at^{2} }$

Answer 2

Answer:

2 m / sec²

Explanation:

Given :

Initial velocity u = 0 m / sec

Final velocity v = 72 km / hr

v in term of m / sec :

= > v = 72 × 5 / 18 m / sec

= > v = 4 × 5 m / sec

= > v = 20 m / sec

Time t =  10 sec

We have to find acceleration a :

Using first equation of motion :

i.e . v = u + a t

= > a = ( v - u ) / t

Putting values here we get :

= > a = ( 20 - 0 ) / 10 m / sec²

= > a = 20 / 10 m / sec

= > a = 2 m / sec²

Hence we get required answer.