What is the probability that a leap year has 53 Sundays or 53 monday ?
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Step-by-step explanation:
A leap year consists of 366 days comprising of 52 weeks and 2 days. There are 7 possibilities for these 2 extra days viz. (i) Sunday, Monday, (ii) Monday, Tuesday, (iii) Tuesday, Wednesday, (iv) Wednesday, Thursday, (v) Thursday, Friday, (vi) Friday, Saturday and (vii) Saturday, Sunday. Let us consider two events : A : the leap year contains 53 Sundays B : the leap year contains 53 Mondays. Then we have P(A) = 2/7, P(B) = 2/7, P(A ∩ B) = 1/7 Hence, required probability = P(A ∪ B) = P(A) + P(B) - P(A ∩ B) = 2/7 + 2/7 - 1/7 = 3/7.
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