Question

A car starts from rest. It
acquires a speed of 25 ms after
20 s. The distance moved by the
car during this time is:
(a) 31.25 m (b) 250 m
(c) 500 m
(d) 5000 m​

Answer 1

Answer:

b) 250m

Explanation:

Given,

initial velocity, u = 0

Final velocity, v = 25ms

Time, t = 20s

Now,

v = u + at

25 = 0 + 20a

a = 25/20

a = 1.25 ms^2

So,

Distance, s = ut + 1/2at^2

s = 0 + 1/2 × 1.25 × 20 × 20

s = 250m