a car starts from rest with constant acceleration of 2m/s. find velocity after 10 seconds.
Answers
Answer:
the car is moving with constant acceleration,we need to use the equations by considering which three variables we can relate.
So,to find the velocity at the end of
5
th second,we can use,
v
=
u
+
a
t
Here,
u
=
0
,
a
=
2
.
t
=
5
(as it started from rest)
So,
v
=
10
m
s
−
1
Distance covered in
5
s
can be found using,
S
=
u
t
+
1
2
a
t
2
So,
S
=
0
+
1
2
2
⋅
5
2
=
25
m
And,speed after covering,
100
m
can be found using,
v
2
=
u
2
+
2
a
s
So,
v
2
=
0
2
+
2
⋅
2
⋅
100
So,
v
=
20
m
s
−
1
ANSWER:-
Given:
A car starts from the rest and moves with a constant acceleration of 2 m/s² for 10 secs
To find:
The velocity of the car after 10 seconds
Solution:
The 1st equation of motion is given by,
v = u + at
where
v = final velocity
u = initial velocity
a = acceleration
t = time
According to the question, the car starts from the rest ∴ u = 0
Now, we will substitute the values of u = 0, a = 2 m/s² and t = 10 s in the above equation of motion,
v = 0 + (2 × 10)
⇒ v = 20 m/s
Thus, the velocity of the car after 10 seconds is 20 m/s.
hope it will help you....