Question

A car starts from retailers and accelerates at 2 m/s^2 for 10 seconds then calculate

1. Final Velocity
2. Distance Travelled By It

Answer 1

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Given :-
U = 0 ( as given there car is in rest )

A = 2 m/${s}^{2}$

T = 10 s

1》Final Velocity ::

Let's use the First Equation of Motion .

V = U + AT
V = 0 + 2×10
V = 20 m/s

2》Distance Travelled ::

Let's use the Third Equation of Motion .

S = UT + $\frac{1}{2}\:A{T}^{2}$

S = 0×10 + $\frac{1}{2}$ 2 × 10×10

S = 0 + 100

S = 100 m $\boxed{Ans}$

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Hope this helps. . . . . . . ☺☺

Answer 2

In this question it is given that,

Acceleration = 2 m/s^2.
Time = 10 s.


1). v= u+at
Since, u is not given, Hence u = 0.
=> V = 0+(2 x 10) m/s
=> v = 20 m/s

2). In order to find distance,

=> S = ut+ 1/2 at^2
=> S = 0 + 1/2 x 2 x 10 x 10
=> S = (10 x 10) m
=> S = 100 m.

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