Question

a car starts its motion from rest with a constant acceleration of 4m/s².What is the average velocity of the car in first 5s of the motion​

Answer 1

Answer:

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Answer 2

Answer:

Correct option is

A

650 m

For 0−5sec,

a=4m/s

2

, Let velocity at 5sec is v and distance is S

1

Using v=u+at ⇒v=0+4×5=20m/s

Using s=ut+

2

1

at

2

⇒S

1

=0+

2

1

×4×5

2

=50m

For next 25sec

v=20m/s

⇒S

2

=20×25=500m

For comes to rest,

u=20m/s , a=−2m/s

2

Using v

2

=u

2

+2as ⇒0=20

2

−2×2×S

3

⇒S

3

=100m

Total distance =S

1

+S

2

+S

3

=50+500+100=650m

Explanation:

hope this answer helpful