Question

a car starts to move at 9 am at a speed of 40 km/h from a place. The second car start at 10am from the same place and meets the first car at 12 noon. Find the speed of second car ?​

Answer 1

answer

D1=40t

Given that car B starts at 10am and will therefore have spent one hour less then car A when it passes it, here the distance D2 travelled by car B is given by,

D2=60(t−1)

When car B passes car A, they are at the same distance from the starting point and therefore D1 = D2 here by substituting the values of D1 and D2 we get the equation as,

40t=60(t−1)

40t=60t−60

20t=60

t=3

As the time when car A started the journey is 9am we add the time t=3 hours to it and get the time as 12am.