Physics, asked by ItzCutesmiley, 9 months ago

A car starts with 5 m/s and accelerates uniformly at 10 m/s^2 and travel a distance of 50 m .Find the final speed of the car ?
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Answers

Answered by akamran2301
0

Answer:

√(1025) m/s or around 32 m/s

Explanation:

Given:

U= 5 m/s (initial speed)

a= 10 m/s^2 (acceleration)

S= 50 m (distance travelled)

(Always write all the given terms to save your time)

You must remember these equations:

V= U + aT

S= UT + 1/2aT^2

V^2= U^2 + 2aS

V is final speed and T is Time of motion.

So we have U, a and S; and we need V

Thus use the last equation.

V^2 = U^2 + 2aS

=> V^2 = 5^2 + 2×10×50

=> V^2 = 25 + 1000

=> V^2 = 1025

=> V = √(1025) m/s

We know 32^2 is 1024.

Hence √(1025) is around 32 m/s.

Hope it helps...

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Answered by Anonymous
5

\huge\mathcal\color{blue}Question:-

A car starts with 5 m/s and accelerates uniformly at 10 m/s^2 and travel a distance of 50 m .Find the final speed of the car ?

\huge{\boxed{\mathfrak{Formula:-}}}

v {}^{2}  = u {}^{2}  + 2as

\huge\mathcal\color{blue}Answer:-

V^2 = 5^2 +2×10×50

V^2 =1025

v \sqrt{1025}

V= 32.01 m/s

FOR MORE INFORMATION :-

  • V is final speed

  • U is initial speed

  • A is acceleration

  • S is distance

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\huge\pink{\mathbb{Hope \: its \: help \: you}}

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