Question

A car starts with 5 m/s and accelerates uniformly at 10 m/s^2 and travel a distance of 50 m .Find the final speed of the car ?​

Answer 1

Initial velocity of the car (u)= 5 m/s

Final velocity of the car (v) = 10 m/s

Time taken for change in velocity (t)= 5 s

Therefore acceleration (a)= [10 m/s - 5 m/s]/ 5 s = 5 m/s /5s = 1 m/s²

Distance covered during these 5 seconds, is found using the relation

s = u t + ½ a t² = 5 m/s× 5 s + ½ 1 m/s² × 5² s²=25 m+ 12.5 m = 37.5 m

So car covers 37.5 m during the period its velocity changes from 5 m/s to 10 m/s.

Answer 2

initial velocity of car (u) = 5 m/s

final velocity of car (v) = 10m/s

Time taken for change in velocity (t) =5s

therefore acceleration (a) = [10m/s -5m/s] /5s

= 5m/s /5s =1m/s^2

Distance covered during these 5 sec is found using relation..

s= ut +1/2 at^2 = 5m/s * 5s + 1/2 1 m/s^2 * s^2= 25m + 12.5m = 37.5m .......