Physics, asked by naima8970, 9 months ago

A car starts with uniform acceleration along a straight road. After 15 seconds, the distance covered by the car is 450 m. The displacement of the car in 15th second

Answers

Answered by Munnakothari4771
0

Explanation:

Distance =speed *time

450=s*15

450/15=speed

Speed or velocity =30m/s

Accl^n=velocity /time

a=30/15

a=2m/s^2

Therefore,, displacement =u+a/2(2t-1)

Displ. =30+(2*15-1)

Displ. =30+29

D=59m

Hope this can help you

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