A car stops in 6 sec after applying brakes while traveling a distance of 15m if the initial velocity of the car is 10m/s find the retardation and the force being applied (mass of the vehicle is 100 kg
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initial velocty = 10 m/s
final vbelocity = 0
distance trabvelled = 15 m
applying
v^2 - u^2 = 2as
0^2 - 10^2 = 2×a×15
a = -6.667
force = m× a
= 100 × -6.667
= -666.7 N
final vbelocity = 0
distance trabvelled = 15 m
applying
v^2 - u^2 = 2as
0^2 - 10^2 = 2×a×15
a = -6.667
force = m× a
= 100 × -6.667
= -666.7 N
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