Question

ABC is an isosceles triangle with a b is equal to AC is equal to 10 centimetre BC is equal to 8 cm find find the altitude on the BC and hence calculate its area

Answer 1

Altitude^2=AC^2-BC^2/4
altitude=2√21
Area =1/2bh
Area=1/2×8×2√21
Area =8√21=36.66