Question

A car takes off from rest abf cover's a distance of 80m on a straight road in 10s . calculate the magnitude of its acceleration

Answer 1

Answer in the pic and i hope it help you.

Answer 2

$\huge{\underline{\underline{.........Answer.........}}}$

$\huge{\underline{Given:-}}$

From rest that means

u = 0 m/s.

S = 80 meters.

t = 10 seconds.

$\huge{\underline{Explanation:-}}$

As "u" "s" and "t" are given it is convenient to use second kinematic equation.

From second kinematic equation.

$\huge{\boxed{\boxed{S = ut + \frac{1}{2} a {t}^{2}}}}$

Substituting the values

${80 = 0 + \frac{1}{2} a \times {10}^{2}}$

${a = \frac{2 \times 80}{100}}$

${a = \frac{160}{100}}$

${a = 1.6 m/s^2}$

$\huge{\boxed{\boxed{a = 1.6 m/s^2}}}$

So, acceleration acquired by the body is 1.6 m/s^2.