A car tarvels was travelling from point a to b at a speed of 20km/hr.after 1and half hr a bus strats from a at a speed of 30km/hr towards
b.the bus reaches 22 minute ahead of the car.find the distance between a and b
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Hey.
Here is the answer.
Let the distance between a and b be x km
so, time taken by car to reach b = x/ 20 hr
and time taken by bus to reach b = x/30 + 1*1/2 hr as bus starts 1*1/2 hr late
According to question , bus reached 22 minutes earlier
so, x/20 - (x/30 + 1*1/2 ) =22/60 hr
or, x/20 - (x/30+3/2) =22/60
or, (3x - 2x )/60 = 22/60 + 3/2
or, x/60 = 22+90 /60=112/60
so, x =112 km
So, distance between a and b is 112 km.
Thanks.
Here is the answer.
Let the distance between a and b be x km
so, time taken by car to reach b = x/ 20 hr
and time taken by bus to reach b = x/30 + 1*1/2 hr as bus starts 1*1/2 hr late
According to question , bus reached 22 minutes earlier
so, x/20 - (x/30 + 1*1/2 ) =22/60 hr
or, x/20 - (x/30+3/2) =22/60
or, (3x - 2x )/60 = 22/60 + 3/2
or, x/60 = 22+90 /60=112/60
so, x =112 km
So, distance between a and b is 112 km.
Thanks.
annuharvanvi:
nice sketching
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