Physics, asked by rajitarane, 7 months ago

A car that is 8 times heavier than a motorcycle is moving at a speed which is just 1/2 the speed of the motorcycle. What will be the amount of work done required to stop the car as compared to that of a motorcycle?

Answers

Answered by alibarmawer
0

Answer:

1/2.

the kinetic energy used to Stop the car will be twice the amount to that of the motorcycle

Answered by smartbrainz
1

The amount of work done to stop the car as compared to motor cycle is equal to  2times

Explanation:

the work done to stop the car is actually equal to the kinetic energy of the car

For the car

Let us consider the mass to be 8m

The velocity is equal to v/2

The work done to stop the car is equal to 0.5 x 8m x v²/4 = mv²

For the motor cycle

The velocity is equal to v

The mass is equal to m

The work done to stop the entire motorcycle is equal to mv²/2

Hence the amount of work done to stop the car as compared to the motorcycle is double

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