Question

a car tracels east for 10 minutes at
60km/hr . It then turns north and travels for 12 minutes at 50km/hr.
Find the resultant displacement of the car from the starting point at the end of 22 minutes

Answer 1

note :-
1km/h = 5/18 m/s
1min = 60 s

Ve = de/te
de = Ve × te
de = 50/3 × 600
de = 10000m = 10⁴m

Vn = dn/tn
dn = Vn×tn
dn = 125/9 × 720
dn = 10000m = 10⁴m

Resultant displacement = Dr

Dr = √de² + dn²
Dr = √10^8 + 10^8
Dr = √2×10^8
Dr = 10^4√2 m

so resultant displacement is 10000√2 meter

Answer 2

Answer:

Explanation:note :-

1km/h = 5/18 m/s

1min = 60 s

Ve = de/te

de = Ve × te

de = 50/3 × 600

de = 10000m = 10⁴m

Vn = dn/tn

dn = Vn×tn

dn = 125/9 × 720

dn = 10000m = 10⁴m

Resultant displacement = Dr

Dr = √de² + dn²

Dr = √10^8 + 10^8

Dr = √2×10^8

Dr = 10^4√2 m

so resultant displacement is 10000√2 meter

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