Question

A car travel from stop a to stop B with a speed of 30 km per hour and then return 2 return back to a with a speed of 50 kilometre per hour find displacement of car distance and average speed of a car jaldi

Answer 1

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Step by step solution:

$Displacement=0\\\\becasue \ car \ traval \ A \ to \ B \ and \ back \ B \ to A\\\\Now \ have \ to \ find \ average \ speed\\\\we \ know \ formula\\\\\frac{2v_{1}v_{2} }{v_{1}+v_{2} }\\\\ Putting \ value \ here\\\\average \ speed=\frac{2 \times30\times50}{30+50}\\\\average \ speed=\frac{2 \times30\times50}{80}\\\\average \ speed=\frac{150}{4} \ km/hr\\\\average \ speed=37.5 \ km/hr$

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Answer 2

Answer:

Displacement=0 (initial and final positions are same)

Distance=AB

Avg. Speed=2AB/t1+t2=2AB/AB/30+AB/50=2X30X50/30+50

=37.5 Km/hr.

Explanation: