A car traveling at 60km/hr uniformly retards for 10sec and reaches at a velocity of 36 km. Find its retardation
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Answered by
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Hey friend!
a = (v-u)/t
Final velocity = 36km/hr
Initial velocity = 60km/hr
Therefore acceleration,
= (36-60)10
= (-24)/10
= - 2•4
Therefore acceleration is -2•4
Since the value is in negative, it must be retardation.
Hence retardation is 2•4 km/hr^2
Thank you!
a = (v-u)/t
Final velocity = 36km/hr
Initial velocity = 60km/hr
Therefore acceleration,
= (36-60)10
= (-24)/10
= - 2•4
Therefore acceleration is -2•4
Since the value is in negative, it must be retardation.
Hence retardation is 2•4 km/hr^2
Thank you!
Answered by
0
retardation means negative acceleration
retardation=v-u/t
v(final velocity)=60km/hr
u( initial velocity)=36km/hr
-acceleration=-60-36/t
-96/t km/hr
-96/t × 5/18
-16×5/3×10seconds
-90/30
=-9/3
=-3
retardation=v-u/t
v(final velocity)=60km/hr
u( initial velocity)=36km/hr
-acceleration=-60-36/t
-96/t km/hr
-96/t × 5/18
-16×5/3×10seconds
-90/30
=-9/3
=-3
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