Question

a car traveling at 72 km ph brakes are applied and the car reduces its speed to 36km/ph after a distance of 10m . find the retardant

Answer 1

Explanation:

Initial speed:- 72000m/3600s=20m/s

Final Speed:-36000m/3600s=10m/s

Distance travelled:- 200m

Let retardation=r

therefore, 100=400-400r(v^2=u^2+2as)

300=400r

r=3/4 m/s^2

Final speed =0

Initial speed= 10m/s

r=3/4m/s^2

therefore, using v^2=u^2+2as

0=100-3/2s

3/2s=100

s=100*2/3

s=66.6666667m

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Answer 2

Answer:

u = 72 km =72*5/18 =20 m/sec

v = 36 km =36*5/18 =10 m/sec

s = 10 m  

v$2$ -u2 =2as

100 -400 =20 s

-15 m/sec2