A car traveling at a speed of 20 m/s due north along the highway makes the right turn on to a side road that heads due east. It takes 50 s for the car to complete the turn. At the end of 50s the car has the speed of 15 m/s along the side road. Determine the magnitude of average acceleration over the 50 s interval
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Answer:0.5m/s^2
For step wise explanation please see the attachment below.
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Explanation:average acceleration=change velocity/time= 0.5 ms-2
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