A car travelled at a velocity of 54km/h is brought to rest by applying brakes in 3s. Calculate its retardation.
Answers
Answered by
2
Answer:
-18
Explanation:
Answered by
5
Answer :
5 m/s²
Explanation :
Given :
u = 54 km/h
v = 0 m/s
t = 3 s
Velocity = 54 km/h
Convert it into m/s
Therefore Velocity = 54*1000/3600 m/s
= 15 m/s
Acceleration = (v - u) / t
= (0 - 15) / 3
= -15 / 3
= -5 m/s²
Here we have to calculate retardation so the negative sign becomes positive.
Therefore Retardation = 5 m/s²
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