Physics, asked by varshasharma2084, 9 months ago

A car travelled at a velocity of 54km/h is brought to rest by applying brakes in 3s. Calculate its retardation.​

Answers

Answered by catherinelinten
2

Answer:

-18

Explanation:

Answered by sarthakshirole06
5

Answer :

5 m/s²

Explanation :

Given :

u = 54 km/h

v = 0 m/s

t = 3 s

Velocity = 54 km/h

Convert it into m/s

Therefore Velocity = 54*1000/3600 m/s

= 15 m/s

Acceleration = (v - u) / t

= (0 - 15) / 3

= -15 / 3

= -5 m/s²

Here we have to calculate retardation so the negative sign becomes positive.

Therefore Retardation = 5 m/s²

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