Question

A car travelled with a velocity of 10m/sand accelerate at 5m/s^2 find the final velocity when it travelled 30m

Answer 1

Initial Velocity (u) = 10 m/secAcceleration (a) = 5 m/sec^2Distance (s) = 30 mFinal velocity (v) = ??
Using Newton's Third law of Motion,
v^2 = u^2 + 2as
=> v^2 = 10^2 + 2 × 5 × 30
=> v^2 = 100 + 300
=> v^2 = 400
=> v = √400
=> v = 20 m/sec_____________________

Answer 2

Answer:

• Final velocity (v) is 20 m/s

Explanation:

Given

• Initial velocity (u) = 10 m/s
• Acceleration (a) = 5 m/s²
• Distance (s) = 30 m

To find

• Final velocity (v)

Solution

↣ Using third equation of motion :

• v² - u² = 2as

↣ Where :-

• v - final velocity
• u - initial velocity
• a - acceleration
• s - distance

↣ On substituting we get :-

• v² - 10² = 2(5)(30)
• v² - 100 = 2(150)
• v² - 100 = 300
• v² = 300 + 100
• v² = 400
• v = √400
• v = 20

↣ Hence, the final velocity (v) is 20 m/s.