Question

A car travelling at 10m/so accelerates uniformly at 2 m/s square. calculate it's velocity after 5 seconds​

Answer 1

Answer:

Explanation:

Using v=u+at,

v(5s)=10m/s+2m/s²x5s = 10m/s+10m/s=20m/s

Answer 2

Given :

▪ Initial velocity of car = 10mps

▪ Acceleration of car = 2m/s$^2$

▪ Time interval = 5s

To Find :

▪ Final velocity of car after given interval of time.

Concept :

✏ Since, acceleration has said to be constant throughout the motion, we can easily apply equation of kinematics to solve this type of questions.

↗ First equation of kinematics :

$\underline{\boxed{\bf{\pink{v=u+at}}}}$

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

Calculation :

$\implies\sf\:v=u+at\\ \\ \implies\sf\:v=10+2(5)\\ \\ \implies\sf\:v=10+10\\ \\ \implies\underline{\boxed{\bf{\orange{v=20\:mps}}}}$