Question

A car travelling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of the car.​

Answer 1

Answer:

car travelling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of the car.

Answer 2

Answer:

28.6 METER

Explanation:

Here, initial velocity, u=22.4m/s

final velocity, v=0 m/s  

Time taken by car to stop  t=2.55s

If a be the acceleration.

Using formula v=u+at,

0=22.4+a(2.55)

We get  a=−$8.78m/s^{2}$  

(negative signs means deceleration of car)

If d be the distance traveled by car.

Using formula $v^{2}-u^{2}=2ad$

$0^{2}-(-22.4)^{2}=2(-8.78)d$

⟹ d=28.6m