Question

A car travelling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of the car. (Assume uniform acceleration)

Answer 1

A car is traveling at a speed of 22.4 m/s and skids to a stop in 2.55 s. So we have following information:

Initial speed of the car i.e u= 22.4 m/s

Final speed of the car i.e. v=0 m/s ( because car stops)

Time taken to come to stopping position t= 2.55 sec

We wish to determine an acceleration (which is in fact a retardation) a=?

We have equation of the motion

v=u+at

0=22.4+2.55xxa

-2.55a=22.4

a=22.4/(-2.55)

=-8.784 ms^(-2)

v^2=u^2+2as

0=(22.4)^2+2xxsxx(-8.784)

-501.76=-17.568s

s=28.56 m

Before car stops it will travel 28.56 m.

Answer 2

Refer the attachment above ..

Hope it Helps !!