Question

A car travelling at 60 km/h overtakes another car travelling at 42 km/h. Assuming each car to be 5.0 m long, find the time taken during the overtake and the total road distance used for the overtake.

Answer 1

Total distance to be

covered in overtaking=

Length of both cars =10m

Time taken= distance/speed 10m/5m/s=2sec

Total distance used for overtaking will be equal to distance covered by car in overtaking + Length of car

=(50/3)x2+5

=100/3+5

=33.3+5

=38.3m

.·. time taken during the overtake and the total road distance used for the overtake is 38.3m

Answer 2

Answer:

1) 2 seconds

2)33.8 m ~ 34m

Explanation:

60-42 = 18km/h = 5m/s  

s = ut+1/2 at^2 with a = 0  

s = 10m (5m to catch up with other car, 5m to clear it)  

10 = 5*t => t = 2s  

To find road distance  

s = ut  

u = 60km/h = 16.7m/s  

s = 16.7 *2 = 33.3m

33.3m +5 =38.3m