A car travelling at 60 km/h overtakes another car travelling at 42 km/h. Assuming each car to be 5.0 m long, find the time taken during the overtake and the total road distance used for the overtake.
Answers
Answered by
10
Total distance to be
covered in overtaking=
Length of both cars =10m
Time taken= distance/speed 10m/5m/s=2sec
Total distance used for overtaking will be equal to distance covered by car in overtaking + Length of car
=(50/3)x2+5
=100/3+5
=33.3+5
=38.3m
.·. time taken during the overtake and the total road distance used for the overtake is 38.3m
Answered by
7
Answer:
1) 2 seconds
2)33.8 m ~ 34m
Explanation:
60-42 = 18km/h = 5m/s
s = ut+1/2 at^2 with a = 0
s = 10m (5m to catch up with other car, 5m to clear it)
10 = 5*t => t = 2s
To find road distance
s = ut
u = 60km/h = 16.7m/s
s = 16.7 *2 = 33.3m
33.3m +5 =38.3m
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