A car travelling at 69 km/h overtakes another car travelling at 33km/h. Assuming each car to be 5.0m long ,find the time taken during the overtake in Seconds.
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Explanation:
A car travelling ast 60 km/h overtakes another car travellign at 42 km/h. Assuming each car to be 5.0 m long, find the time taken during the overtake aned the total road distance used for the overtake. =s+5=33.3+5
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Initial velocity of the car = 69 km /hr
In order to convert this into m /s multiply by 5 / 18
- Initial velocity = 69 × 5 / 18 = 19.16 m/s
Final velocity of the car = 33 km /hr
In order to convert this into m /s multiply by 5 / 18
- Final velocity = 33 × 5 / 18 = 9.16 m/s
Relative velocity of the car
= 19.16 - 9.16
= 10 m /s
- Length of each car = 5m
- Distance traveled by the car 1 when it overtakes car 2 = 5 + 5 = 10
Time taken by the car 1 to overtake car 2
= Distance / Relative velocity
= 10 / 10
= 1 sec
Time taken by car 1 to overtake car 2 = 1 sec
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