Physics, asked by yasodhadanam, 5 months ago

A car travelling at 69 km/h overtakes another car travelling at 33km/h. Assuming each car to be 5.0m long ,find the time taken during the overtake in Seconds.

Answers

Answered by gkour1234
2

Explanation:

A car travelling ast 60 km/h overtakes another car travellign at 42 km/h. Assuming each car to be 5.0 m long, find the time taken during the overtake aned the total road distance used for the overtake. =s+5=33.3+5

I hope this is helpful to you

Answered by Atαrαh
4

\bigstar\huge\underline{\mathtt{Solution :}}

Initial velocity of the car = 69 km /hr

In order to convert this into m /s multiply by 5 / 18

  • Initial velocity = 69 × 5 / 18 = 19.16 m/s

Final velocity of the car = 33 km /hr

In order to convert this into m /s multiply by 5 / 18

  • Final velocity = 33 × 5 / 18 = 9.16 m/s

Relative velocity of the car

= 19.16 - 9.16

= 10 m /s

  • Length of each car = 5m
  • Distance traveled by the car 1 when it overtakes car 2 = 5 + 5 = 10

Time taken by the car 1 to overtake car 2

= Distance / Relative velocity

= 10 / 10

= 1 sec

Time taken by car 1 to overtake car 2 = 1 sec

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