A car travelling at 72km/hr decelerates uniformly at 2m/s². Calculate (a) the distance it goes before it stops. (b) the time it takes to stop and (c) the distance it travels during the first and third seconds.
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v=u+atv=u+at
0=20+(−2)t0=20+(−2)t
−20=−2t−20=−2t
t=10seconds.
v2=u2+2axv2=u2+2ax
(0)2=(20)2+2(−2)x(0)2=(20)2+2(−2)x
0=400−4x0=400−4x
−400=−4x−400=−4x
x=100metres.
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0=20+(−2)t0=20+(−2)t
−20=−2t−20=−2t
t=10seconds.
v2=u2+2axv2=u2+2ax
(0)2=(20)2+2(−2)x(0)2=(20)2+2(−2)x
0=400−4x0=400−4x
−400=−4x−400=−4x
x=100metres.
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time taken is 10s and distance travelled is 300 m
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