A car travelling at a speed of 10 m/s is bought to rest in 20 seconds by applying brakes calculate the acceleration and distance travelled during this time
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v = u+at
v will be 0 as the car will be stopped
0 = 10 + a×20
a = -10/20
a = -0.5 m/s^2
here negative shows retardation
s = 10×20 + 0.5 (0.5)×20×20
s = 200 + 100
s = 300 m
v will be 0 as the car will be stopped
0 = 10 + a×20
a = -10/20
a = -0.5 m/s^2
here negative shows retardation
s = 10×20 + 0.5 (0.5)×20×20
s = 200 + 100
s = 300 m
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Explanation:
s= 300m......
Pihu ❤️ Sam
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