A car travelling at a speed of 30km/h is brought to rest in a distance of 8m by appying breaks if the same car is moving at the distance 60km/h. calculate the dostance at which it is brought to rest
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u=30*5/18m/s
=25/3m/s
v=0m/s
s=8m
v^2-u^2=2as
0-625/9=16a
a=-625/144
now.
u=60*5/18
=50/3m/s
v=0
v^2-u^2=2as
0-2500/9=2*-625/144s
s=2500*72/9*625
s=32m
=25/3m/s
v=0m/s
s=8m
v^2-u^2=2as
0-625/9=16a
a=-625/144
now.
u=60*5/18
=50/3m/s
v=0
v^2-u^2=2as
0-2500/9=2*-625/144s
s=2500*72/9*625
s=32m
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