Question

. A car travelling at a speed of 72 km/h is brought to rest in 2s by the application of brakes. The distance covered by the car in 2s is?

Answer 1

Answer:

20 metres

Step-by-step explanation:

Using third eqn of motion

V² - U² = 2 as

Finding a

72km/hr = 20m/s = U

0 m/s = V

t= 2 sec (given)

So a =( V - U )/ t = ( 0–20 )/ 2 = -10m/s²

Putting above in equation of motion we have

0² - 20² = 2*(-10)* s

s = 20 metres

PLZ MARK ME AS BRAINLIEST

Answer 2

Step-by-step explanation:

Speed = 72 km/hr

Time = 2 second

Distance covered in one second = 72 / 3600 = 0.02 km/sec

Distance covered in 2 second = 2 × 0.02 = 0.04 km

Distance covered = 0.04 × 1000 = 40 m