Question

a car travelling at a velocity of 54 km per hour stops in 6 seconds after brakes are applied how much force do the brakes applied to the car if the mass of the car along with this driver is 800 kg​

Answer 1

Explanation:

Force=mass× acceleration

given mass = 800kg

v=0

u= 15 m/s

t=6s

v=u+at

0=15-a6( since body is decelarated)

a=15/6=5/2=2.5m/s2

f= 800×2.5

= 2000N

Im not sure abt the answer,Hope it helped you!

Answer 2

Answer:

2.59 x 10⁷ N

Explanation:

Initial Velocity of car, u = 54 km/h

Final Velocity of car, v = 0 km/h

Time taken by the car to stop, t = 6s = $\frac{6}{60 x 60}$ hr = 1.67 x 10⁻³ hr.

Mass of the car, m = 800 kg

We know that, Acceleration, a = $\frac{v-u}{t}$ = $\frac{0-54}{1.67}$ x 10³ = -32.33 x 10³

Now, Force, F = ma = 800 x -32.33 x 10³ = -25868.26 x 10³ = 2.59 x 10⁷N

Hope this helps.....