Question

A car travelling at speed of 30 m/s applies brake and comes to rest in 5 seconds.How much distance does the car travels before coming to rest.

Answer 1

Answer:

$inital \: velocity (u) = 30 \frac{m}{s}$

$final \: velocity (v) = 0 \frac{m}{s} \: \: \: \: \: \: \: as \: the \: car \: comes \: to \: rest$

$time(t) = 5s$

$acceleration(a) = \frac{v - u}{t}$

$a = \frac{0 - 30}{5}$

$a = \frac{ - 30}{5}$

$a = - 6 \frac{m}{s ^{2} }$

$by \: using \: second \: equation \: of \: motion \:$

$distance(s) = ut + \frac{1}{2} at ^{2}$

$s = 30 \times 5 + \frac{1}{2} \times - 6 \times 5 ^{2}$

$s = 600 - 3 \times 25$

$s = 600 - 75$

$s = 525m$

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