Question

Anyone Please Help me
Maths..

Answer 1

Answer:

Step-by-step explanation:

f(x)=x²+11x+30

here a=1,b=11,c=30

x²+6x+5x+30

=x(x+6)+5(x+6)

=(x+5)(x+6)

x+5=0,x=-5

x+6=0,x=-6

so zeros

α=-5,β=-6

Now αβ=(-5)(-6)=30=30/1=c/a

so αβ=c/a

================

α+β=-5-6=-11

=-(11/1)=-b/a

α+β=-b/a

==============================================

(ii)  f(x)=x²-9=x²-0*x-9

Here a=1,b=0,c=-9

(x-3)(x+3)

x-3=0,,x=3

x+3=0,x=-3

So zeros

α=3,β=-3

=============

Now αβ=(3)(-3)=-9=-9/1=c/a

so αβ=c/a

==============

α+β=3-3=0

=-0/1=-b/a

α+β=-b/a

==================================

Hence relation between coefficients and zeros is verified