A car travelling in a straight line has a velocity of 5.0 ms–1 at some instant. After 4.0 s, its velocity is 8.0 ms–1. What is its average acceleration in this time interval?
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Answer:
axasaa
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Explanation:
u=5.0m/s
t=4.0a
v=8.0m/s
Average acceleration = a= u (v-u)/t
= a = (8.0-5.0)/4.0
= a = 3.0/4.0
= a = 0.75 ms square
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