Question

A car travelling ng at 4m/s and accelerates with uniform acceleration at 3m/s^2 for 6s it's final velocity will be

Answer 1

Answer:

Initial velocity is: u=0

Acceleration is: a=4 ms

2

Time is: t=10 s

Using second equation of motion:

s=ut+

2

1

at

2

s=0×10+

2

1

×4×10

2

=0+200=200 m

Answer 2

Answer:

The final velocity of the car is 22 m/s.

Explanation:

The initial velocity of the car, u = 4 m/s

The acceleration of the car, a = 3 m/s²

Time taken for the acceleration, t = 6 s

The final velocity of the car can be found from the 1st equation of motion.

v = u + at

v = 4 + (3 × 6)

v = 4 + 18

∴ Final velocity, v = 22 m/s