A car travelling with a speed of 90km/h on a straight road is ahead of ascooter travelling with a speed of 50km/h. How would the relative velocity be attened .if scooter is ahead of car
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Explanation:
if scooter is ahead of car
then, from ground frame of reference
scooter is ata speed of 50km/hr and car at 90 km /hr.
From car frame of reference scooter is moving bachwards with a speed of 90-50 km/hr = 40km/hr
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Answer:
let velocity of car be v1 = 90kmh
let velocity of scooter be v2 = 60 kmh
the relative velocity of car wrt scooter = v1-v2 = 90 - 60 = 30 kmh
whereas the relative velocity if positions are alterd will be v2-v1 = 60 - 90 = -30 kmh
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