A car travels 1/3 of the distance on a straight road with a velocity of 10 km/hr , next 1/3 with velocity of 20 km/hr and the last 1/3 with velocity of 60 km/hr. what is the average velocity of the car in the whole journey?
Payal001:
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Answers
Answered by
85
Let the total distance travelled be x.
Let the total time taken be T.
Average speed = Total distance/Total time = x/T
First half,
v = 10 km/h
s = 1/3 x
t= x/3/10 = x/30
Second half,
v = 20 km/h
s = 1/3 x
t= x/3/20 = x/60
Third half,
v = 60 km/h
s = 1/3 x
t = x/3/60 = x/180
Now,
Time for entire journey, T = x/30 + x/60 + x/180
Or T = 6x + 3x + x/180
Or T= 10x/180
Or T = x/18
Now,
Average speed of the entire journey, Vav = Total distance/Total time
= x/x/18
= 18 km/h
Let the total time taken be T.
Average speed = Total distance/Total time = x/T
First half,
v = 10 km/h
s = 1/3 x
t= x/3/10 = x/30
Second half,
v = 20 km/h
s = 1/3 x
t= x/3/20 = x/60
Third half,
v = 60 km/h
s = 1/3 x
t = x/3/60 = x/180
Now,
Time for entire journey, T = x/30 + x/60 + x/180
Or T = 6x + 3x + x/180
Or T= 10x/180
Or T = x/18
Now,
Average speed of the entire journey, Vav = Total distance/Total time
= x/x/18
= 18 km/h
Answered by
3
Answer:
18 km/hr
Explanation :
Let the total distance travelled be x km Then total time taken = 10x/3+20x/3+60x/3=30x+60x+180x
=1806x+3x+x=18010x=18x hrs Then average speed = =TotaltimetakenTotaldistancetravelled
=x/18x km/hr = 18 km/hr
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