A car travels 30 km with a uniform speed of 30km hr what will be its speed for next 90 km if average sppedd for whole journey is 60 km hr
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Answered by
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s=d/t
s=d1+d2/t1+t2
60=30+90/t1+t2
t1=d1/s1=30/30hr
t1=1hr
hence60=120/1+t2
1+t2=2
t2=1
therefore s2=d2/t2
s2=90/1hr
s2=90km/hr
s=d1+d2/t1+t2
60=30+90/t1+t2
t1=d1/s1=30/30hr
t1=1hr
hence60=120/1+t2
1+t2=2
t2=1
therefore s2=d2/t2
s2=90/1hr
s2=90km/hr
Answered by
0
distance = 30 km , speed = 30 km/hr
therefore time = 1 hr (time = distance/speed)
average distance = (total distance/total time taken)
total distance = 90 + 30 = 120 km
total time taken = 1hr + xhr
therefore
120/(1+x) = 60 => x = 1 hr (time for the second journey of 90 km)
therefore
speed = 90/1 = 90km/hr
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