a car travels 30km at uniform speed of 40km/h and the next 30km at a uniform speed of 20km/h.calculate its average speed in m/s...plz give the answer by a part...very urgent
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hey dear [^-^]
ur answer is here................
given that ,
1st 30 km uniform speed is (u1) = 40 km/h
2nd 30 km uniform speed is ( u2 ) = 20 km/h
total distance ( d ) = 30 + 30 = 60 km
time taken in 1st time = d / t = 30/40 also, 3h / 4 = 180/4 = 45 min
tim taken in 2nd time = d/t = 30/20 also, 3h/2 = 180/2 = 90 min
total time = 45 + 90 = 135 min = 135/60 h
av.speed = 60/135/60 = 60 * 60 /135 = 26.66 km/h ( answer )
_________________________________________
^_^≈≈≈≈hope its hlp uh≈≈≈≈≈ ^_^
ur answer is here................
given that ,
1st 30 km uniform speed is (u1) = 40 km/h
2nd 30 km uniform speed is ( u2 ) = 20 km/h
total distance ( d ) = 30 + 30 = 60 km
time taken in 1st time = d / t = 30/40 also, 3h / 4 = 180/4 = 45 min
tim taken in 2nd time = d/t = 30/20 also, 3h/2 = 180/2 = 90 min
total time = 45 + 90 = 135 min = 135/60 h
av.speed = 60/135/60 = 60 * 60 /135 = 26.66 km/h ( answer )
_________________________________________
^_^≈≈≈≈hope its hlp uh≈≈≈≈≈ ^_^
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