Question

A car travels 40 km at uniform speed 90 km/hr and next 60 km at the uniform speed of 15 km/hr find its average speed

Answer 1

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Car travels 40km at 90km/hr

Car travels 40km at 90km/hrCar travels 60km at 15km/hr

Time taken In 1st case

Time taken In 1st case distance = 40km

Time taken In 1st case distance = 40kmspeed = 90km/hr

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hr

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hrdistance= 60km

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hrdistance= 60kmtime = d/s

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hrdistance= 60kmtime = d/s = 60/15. = 4hr

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hrdistance= 60kmtime = d/s = 60/15. = 4hrtotal time taken in both section = 4/9 ± 4 = 4.4hrs

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hrdistance= 60kmtime = d/s = 60/15. = 4hrtotal time taken in both section = 4/9 ± 4 = 4.4hrsAverage speed = Total distance covered

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hrdistance= 60kmtime = d/s = 60/15. = 4hrtotal time taken in both section = 4/9 ± 4 = 4.4hrsAverage speed = Total distance covered Total time taken

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hrdistance= 60kmtime = d/s = 60/15. = 4hrtotal time taken in both section = 4/9 ± 4 = 4.4hrsAverage speed = Total distance covered Total time taken = 100.

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hrdistance= 60kmtime = d/s = 60/15. = 4hrtotal time taken in both section = 4/9 ± 4 = 4.4hrsAverage speed = Total distance covered Total time taken = 100. 4.4

Time taken In 1st case distance = 40kmspeed = 90km/hrt = d / s= 40/90 = 4.4Time taken in 2nd case speed = 15km/hrdistance= 60kmtime = d/s = 60/15. = 4hrtotal time taken in both section = 4/9 ± 4 = 4.4hrsAverage speed = Total distance covered Total time taken = 100. 4.4= 22.7km/hr

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