a car travels 8m toward north with the speed of 2m/s and then 6m towards south with the speed of 3m/s.Find the magnitude of average velocity
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the time for travel 8m is 4sec,
the time for travel 6m is 2sec,
the net displacement from his starting point is √(8^2+6^2)=10,
the magnitude of average velocity is =10÷(4+2)=10÷6
the time for travel 6m is 2sec,
the net displacement from his starting point is √(8^2+6^2)=10,
the magnitude of average velocity is =10÷(4+2)=10÷6
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