A car travels at 54 km/h for first 20s, 36km/h for next 30s and finally 18 km/h for next 10s. Find its average speed.
Answers
Answered by
1348
54 km/hr = 54 x 5/18 = 15 m/s
36 km/hr = 36 x 5/18 = 10 m/s
18 km/hr = 18 x 5/18 = 5 m/s
1st Case ---
Speed = 15m/s
Time = 20 s
Distance = Speed x Time = 15 x 20 = 300 m
2nd Case ---
Speed = 10 m/s
Time = 30 sec
Distance = 10 x 30 = 300 m
3rd Case ---
Speed = 5 m/s
Time = 10s
Distance = 5 x 10 = 50 m
Now Total Distance = 300 + 300 + 50 = 650 m
Total time = 20 + 30 + 10 = 60 s
Average Speed = 650/60 = 65/6 m/s
Hope This Helps You!
36 km/hr = 36 x 5/18 = 10 m/s
18 km/hr = 18 x 5/18 = 5 m/s
1st Case ---
Speed = 15m/s
Time = 20 s
Distance = Speed x Time = 15 x 20 = 300 m
2nd Case ---
Speed = 10 m/s
Time = 30 sec
Distance = 10 x 30 = 300 m
3rd Case ---
Speed = 5 m/s
Time = 10s
Distance = 5 x 10 = 50 m
Now Total Distance = 300 + 300 + 50 = 650 m
Total time = 20 + 30 + 10 = 60 s
Average Speed = 650/60 = 65/6 m/s
Hope This Helps You!
surovideb1409:
Thanks
Answered by
270
Answer:
54 km/hr = 54 x 5/18 = 15 m/s
36 km/hr = 36 x 5/18 = 10 m/s
18 km/hr = 18 x 5/18 = 5 m/s
1st Case ---
Speed = 15m/s
Time = 20 s
Distance = Speed x Time = 15 x 20 = 300 m
2nd Case ---
Speed = 10 m/s
Time = 30 sec
Distance = 10 x 30 = 300 m
3rd Case ---
Speed = 5 m/s
Time = 10s
Distance = 5 x 10 = 50 m
Total Distance = 300 + 300 + 50 = 650 m
Total time = 20 + 30 + 10 = 60 s
Average Speed = 650/60 = 65/6 m/s
Explanation:
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