Question

A car travels at a certain distance at a speed of 50 km h and returns at 40 km h find avearage speed and velocity

Answer 1

ʜᴇʟʟᴏ ᴍᴀᴛᴇ!

ʟᴇᴛ ᴛʜᴇ ᴅɪsᴛᴀɴᴄᴇ ʙᴇ ᴅ

sᴘᴇᴇᴅ = ᴅɪsᴛᴀɴᴄᴇ / ᴛɪᴍᴇ

50 = ᴅ / ᴛ1
ᴛ1 = ᴅ / 50

40 = ᴅ / ᴛ2
ᴛ2 = ᴅ / 40

ᴀᴠᴇʀᴀɢᴇ sᴘᴇᴇᴅ = ᴛᴏᴛᴀʟ ᴅɪsᴛᴀɴᴄᴇ / ᴛᴏᴛᴀʟ ᴛɪᴍᴇ
= ( ᴅ + ᴅ )/( ᴛ1 + ᴛ2 ) = 2ᴅ / ( ᴅ/50 + ᴅ/40 )

= 2ᴅ / ( 4ᴅ + 5ᴅ )/200
= 2 / 9 × 200 = 400 / 9 = 44.4 ᴋᴍ/ʜ

ᴀᴠᴇʀᴀɢᴇ ᴠᴇʟᴏᴄɪᴛʏ = 44.4 ᴋᴍ/ʜ

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs

Answer 2

✬ 44.44 km/h ✬

Explanation:

Given:

• Speed in car during forward direction (v¹) = 50 km/h
• Speed of car during returning (v²) = 40 km/h

To Find:

• What is the average speed of the car?

Solution: Let the distance travelled by car in forward direction be x. Therefore, distance travelled during returning will also be x.

• Total Distance covered by car = x + x = 2x

• We know that Time = Distance/Speed

• ∴ Time (t¹) during forward direction = x/50 h
• and time (t¹) during return journey = x/40 h

• Total time taken by car during whole journey •

$\small\implies{\sf }$ t¹ + t²

$\small\implies{\sf }$ x/50 + x/40 [ Take LCM ]

$\small\implies{\sf }$ 4x + 5x/200

$\small\implies{\sf }$ 9x/200 h

★ Average Speed = Total Distance/ Total Time ★

$\small\implies{\sf }$ 2x/9x/200

$\small\implies{\sf }$ 2x(200)/9x

$\small\implies{\sf }$ 400x/9x

$\small\implies{\sf }$ 400/9

$\small\implies{\sf }$ 44.44 km/h

Hence, The average velocity of car is 44.44 km/h