Question

A car travels at a uniform velocity of 60 m s-1
for 10 s and is brought to rest in 5s. The
retardation of the car and the distance travelled
in 15s is
a) 10 m s?, 1750m b) 12m s 2,350 m​

Answer 1

U= 60 m/s

t = 10 sec

a =0

s= ut +(1/2)at²

 = 60×10  +0

 = 600 m

now, u = 60 m/s

v =0

t =5 sec

as, v= u+at

⇒0 = 60 + a×5

⇒5a = -60

⇒a = - 12 m/s²

also, s = ut +(1/2)at²

           = 60×5 +(1/2)×(-12)×(5)²

           = 150 m

 Total distance = 600+150 = 750 m