Physics, asked by ar12673, 10 months ago

A car travels at a uniform velocity of 60 metres second-1 for 10 seconds and it is brought to rest in 5 seconds calculate the the r e t a r r d a t i o n of the car and distance travelled in 15 seconds​

Answers

Answered by KAI1217
2

retardation of car is 48

distances in 15 sec is 65

Answered by jadhavscienceclasses
2
u= 60m/s
v=0m/s
t=5
a=(v-u)/t
a=0-60/5
a= -12m/s^2
speed=distance/time
distance =speed X time
distance=60m/s X 15
= 900m
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